Help with regular expression in python

Martin Komoň M.Komon at SiliconHill.cz
Thu Aug 18 21:59:32 CEST 2011


You don't seem to account for the whitespace between the floats. Try
> '([-+]?(\d+(\.\d*)?|\.\d+)([eE][-+]?\d+)?\s+){32}'
(just added \s+).

Martin

On 8/18/2011 9:49 PM, Matt Funk wrote:
> Hi,
> i am sorry if this doesn't quite match the subject of the list. If someone 
> takes offense please point me to where this question should go. Anyway, i have 
> a problem using regular expressions. I would like to match the line:
> 
> 1.002000e+01 2.037000e+01 2.128000e+01 1.908000e+01 1.871000e+01 1.914000e+01 
> 2.007000e+01 1.664000e+01 2.204000e+01 2.109000e+01 2.209000e+01 2.376000e+01 
> 2.158000e+01 2.177000e+01 2.152000e+01 2.267000e+01 1.084000e+01 1.671000e+01 
> 1.888000e+01 1.854000e+01 2.064000e+01 2.000000e+01 2.200000e+01 2.139000e+01 
> 2.137000e+01 2.178000e+01 2.179000e+01 2.123000e+01 2.201000e+01 2.150000e+01 
> 2.150000e+01 2.199000e+01 : (instance: 0)	:	some description
> 
> The number of floats can vary (in this example there are 32). So what i thought 
> i'd do is the following:
> instance_linetype_pattern_str = '([-+]?(\d+(\.\d*)?|\.\d+)([eE][-+]?\d+)?)
> {32}'
> instance_linetype_pattern = re.compile(instance_linetype_pattern_str)
> Basically the expression in the first major set of paranthesis matches a 
> scientific number format. The '{32}' is supposed to match the previous 32 
> times. However, it doesn't. I  can't figure out why this does not work. I'd 
> really like to understand it if someone can shed light on it.
> 
> thanks
> matt



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