Help on PyQt4 QProcess

Phil Thompson phil at riverbankcomputing.com
Fri Aug 19 19:56:30 CEST 2011


On Fri, 19 Aug 2011 10:15:20 -0700 (PDT), Edgar Fuentes
<fuentesej at gmail.com> wrote:
> Dear friends,
> 
> I need execute an external program from a gui using PyQt4, to avoid
> that hang the main thread, i must connect the signal "finished(int)"
> of a QProcess to work properly.
> 
> for example, why this program don't work?
> 
>    from PyQt4.QtCore import QProcess
>    pro = QProcess() # create QProcess object
>    pro.connect(pro, SIGNAL('started()'), lambda
> x="started":print(x))        # connect
>    pro.connect(pro, SIGNAL("finished(int)"), lambda
> x="finished":print(x))
>    pro.start('python',['hello.py'])        # star hello.py program
> (contain print("hello world!"))
>    timeout = -1
>    pro.waitForFinished(timeout)
>    print(pro.readAllStandardOutput().data())
> 
> output:
> 
>    started
>    0
>    b'hello world!\n'
> 
> see that not emit the signal finished(int)

Yes it is, and your lambda slot is printing "0" which is the return code
of the process.

Phil



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