Compare tuples of different lenght
steve+comp.lang.python at pearwood.info
Sat Aug 20 12:17:39 CEST 2011
Jurgens de Bruin wrote:
> I have a list of tuples:
> I would like to compare all the tuples to each other and if one
> element if found two tuples the smallest tuples is removed from the
It's not clear what you mean by "smallest" tuple. Is (8,) smaller than
I'm going to guess you care only about the length of the tuple, and not the
Let's start with a couple of helper functions.
def compare(t1, t2):
'Return -1 if t1 is "smaller" than t2, 0 if equal, and +1 if "bigger".'
if len(t1) < len(t2): return -1
elif len(t1) > len(t2): return 1
else: return 0
def match_any_item(t1, t2):
s1 = set(t1)
s2 = set(t2)
return bool(s1 & s2)
# Can't convert to sets because at least one item is mutable.
# Let's do this the slow(?) way.
matched = [x for x in t1 if x in t2]
list_of_tuples = [(2,),(12,13),(2,3,4),(8,),(5,6),(7,8,9),]
flags = [True]*len(list_of_tuples)
for i,t1 in enumerate(list_of_tuples):
for j in range(i+1, len(list_of_tuples)):
t2 = list_of_tuples[j]
if match_any_item(t1, t2):
n = compare(t1, t2)
if n == -1:
# Flag t1 to be removed.
flags[i] = False
elif n == 1:
# Flag t2 to be removed.
flags[j] = False
saved_tuples = 
for t,flag in zip(list_of_tuples, flags):
if flag: saved_tuples.append(t)
[(12, 13), (2, 3, 4), (5, 6), (7, 8, 9)]
which matches what you wanted:
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