On Fri, Aug 5, 2011 at 1:40 AM, Dan Stromberg <drsalists at gmail.com> wrote: >>>> print int(hex(0x72).replace('0x', '')) > 72 Or simpler: int(hex(0x72)[2:]) Although if you have it as a string, you need to ord() the string. It's probably better to just do the bitwise operations though. ChrisA