Weird interaction with nested functions inside a decorator-producing function and closuring of outer data...
Adam Jorgensen
adam.jorgensen.za at gmail.com
Wed Aug 24 10:30:13 EDT 2011
Thanks :-) Sorry about the size, I wasn't sure what was relevant...
On 24 August 2011 15:29, Peter Otten <__peter__ at web.de> wrote:
> Adam Jorgensen wrote:
>
>> Hi all, I'm experiencing a weird issue with closuring of parameters
>> and some nested functions I have inside two functions that
>> return decorators. I think it's best illustrated with the actual code:
>
> You should have made an effort to reduce its size
>> # This decorator doesn't work. For some reason python refuses to
>> closure the *decode_args parameter into the scope of the nested
>> decorate and decorate_with_rest_wrapper functions
>> # Renaming *decode_args has no effect
>> def rest_wrapper(*decode_args, **deco_kwargs):
>> def decorate(func):
>> argspec = getfullargspec(func)
>> decode_args = [argspec.args.index(decode_arg) for decode_arg
>> in decode_args]
>
> I didn't read the whole thing, but:
>
>>>> def f(a):
> ... def g():
> ... a = a + 42
> ... return a
> ... return g
> ...
>>>> f(1)()
> Traceback (most recent call last):
> File "<stdin>", line 1, in <module>
> File "<stdin>", line 3, in g
> UnboundLocalError: local variable 'a' referenced before assignment
>
> Python treats variables as local if you assign a value to them anywhere in
> the function. The fix is easy, just use another name:
>
>>>> def f(a):
> ... def g():
> ... b = a + 42
> ... return b
> ... return g
> ...
>>>> f(1)()
> 43
>
> In Python 3 you can also use the nonlocal statement.
>
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