adding elements to set
Duncan Booth
duncan.booth at invalid.invalid
Thu Dec 8 13:54:30 EST 2011
Chris Angelico <rosuav at gmail.com> wrote:
> On Fri, Dec 9, 2011 at 4:32 AM, Peter Otten <__peter__ at web.de> wrote:
>> The only thing that has changed (in 2.7) is the algorithm to
>> calculate the hash value. The bits are rotated to turn the four least
>> significant bits into the most signicant ones. According to a comment
>> in Objects/objects.c the change leads to fewer hash collisions.
>
> Interesting, but what I saw was this:
>
>>>> class C(object):
>
> def __init__(self, x):
> self.x = x
>
> def __eq__(self, other):
> return self.x == other.x
>
>>>> s=set()
>>>> c1=C(1)
>>>> s.add(c1)
> Traceback (most recent call last):
> File "<pyshell#163>", line 1, in <module>
> s.add(c1)
> TypeError: unhashable type: 'C'
>
> (This is in IDLE from Python 3.2 on Windows.)
>
> However, s.add(object()) works fine. So subclasses don't get that.
> Odd. Makes sense though - you can't get this unexpected behaviour as
> easily.
>
Yes, the documentation describes this although I don't think anything
highlights that it is a change from Python 2.x:
[http://docs.python.org/py3k/reference/datamodel.html]
> If a class does not define an __eq__() method it should not define a
> __hash__() operation either; if it defines __eq__() but not
> __hash__(), its instances will not be usable as items in hashable
> collections. If a class defines mutable objects and implements an
> __eq__() method, it should not implement __hash__(), since the
> implementation of hashable collections requires that a key’s hash
> value is immutable (if the object’s hash value changes, it will be in
> the wrong hash bucket).
So in Python 2.x you could define __eq__ and get the default __hash__ which
would break dictionaries. With Python 3.x defining __eq__ will disable the
default __hash__ although if you subclass a class that has both methods you
could still get in a mess by redefining one without the other.
--
Duncan Booth http://kupuguy.blogspot.com
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