test for list equality
MRAB
python at mrabarnett.plus.com
Thu Dec 15 12:54:21 EST 2011
On 15/12/2011 16:36, noydb wrote:
> I want to test for equality between two lists. For example, if I have
> two lists that are equal in content but not in order, I want a return
> of 'equal' -- dont care if they are not in the same order. In order
> to get that equality, would I have to sort both lists regardless? if
> yes, how (having issues with list.sort)?
>
> Another way i tried, that I think is kind-of roundabout is like
> x = [2, 5, 1, 88, 9]
> y = [5, 2, 9, 1, 88]
> inBoth = list(set(x)& set(y))
>
> and then test that list.count is equal between inBoth and x and/or y.
>
>
> Any better suggestions?
>
> Thanks for any help!
You could count the number of times each item occurs using the Counter
class in the collections module:
>>> x = [2, 5, 1, 88, 9]
>>> y = [5, 2, 9, 1, 88]
>>> from collections import Counter
>>> cx = Counter(x)
>>> cy = Counter(y)
>>> cx
Counter({88: 1, 1: 1, 2: 1, 5: 1, 9: 1})
>>> cx == cy
True
More information about the Python-list
mailing list