Transform two tuples item by item

[Tim Chase]

On 12/19/11 20:04, Gnarlodious wrote:
> What is the best way to operate on a tuple of values
> transforming them against a tuple of operations? Result can be
> a list or tuple:
>
> tup=(35, '34', 0, 1, 31, 0, '既濟')
>
> from cgi import escape
> [tup[0], "<span> class='H'>{}</span>".format(tup[1]), bool(tup[2]),
> bool(tup[3]), tup[4], bool(tup[5]), escape(tup[6])]
>
> ->  [35, "<span class='H'>34</span>", False, True, 31, False,
> '&#26082;&#28639;']
>
> But I want to loop rather than subscripting.

Well, you can do something like

 >>> from cgi import escape
 >>> nop = lambda x: x
 >>> tup = (35, '34', 0, 1, 31, 0, '既濟')
 >>> ops = [nop, "<span class='H'>{0}</span>".format, bool, bool, 
nop, bool, escape]
 >>> [f(x) for f, x in zip(ops,tup)]
[35, "<span class='H'>34</span>", False, True, 31, False, 
'&#26082;&#28639;']

Note #1: I had to change your format from "{}" to "{0}", at least 
in 2.6 I've got here)

Note #2: it's spelled ".format" not ".format()" which puts the 
function reference in the "ops" list, not the results of calling it.

-tkc