Arrays/List, filters, Pytho, Ruby
Chris Rebert
clp2 at rebertia.com
Fri Feb 11 22:44:26 CET 2011
On Fri, Feb 11, 2011 at 1:24 PM, LL.Snark <ll.snark at gmail.com> wrote:
> Hi,
>
> I'm looking for a pythonic way to translate this short Ruby code :
> t=[6,7,8,6,7,9,8,4,3,6,7]
> i=t.index {|x| x<t.first}
>
> If you don't know Ruby, the second line means :
> What is the index, in array t, of the first element x such that x<t[0].
>
> If can write it in python several ways :
> t=[6,7,8,6,7,9,8,4,3,6,7]
> i=0
> while t[i]>=t[0] : i+=1
>
> ... not pythonic I think...
>
> Or :
> t=[6,7,8,6,7,9,8,4,3,6,7]
> i=[j for j in range(len(t)) if t[j]<t[0]][0]
>
> ...too cryptic...
>
> I'm using Python 3.
My version:
t = [6,7,8,6,7,9,8,4,3,6,7]
i = -1
for index, item in enumerate(t):
if item < t[0]:
i = index
break
I'm a big fan of enumerate().
I'm sure an itertools solution is also possible.
Cheers,
Chris
--
http://blog.rebertia.com
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