pattern matching

Steven D'Aprano steve+comp.lang.python at pearwood.info
Thu Feb 24 03:37:31 CET 2011


On Wed, 23 Feb 2011 21:11:53 -0500, monkeys paw wrote:

> if I have a string such as '<td>01/12/2011</td>' and i want to reformat
> it as '20110112', how do i pull out the components of the string and
> reformat them into a YYYYDDMM format?

data = '<td>01/12/2011</td>'
# Throw away tags.
data = data[4:-5]
# Separate components.
day, month, year = data.split('/')
# Recombine.
print(year + month + day)


No need for the sledgehammer of regexes for cracking this peanut.



-- 
Steven



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