Python subprocesses experience mysterious delay in receiving stdin EOF
Yang Zhang
yanghatespam at gmail.com
Wed Feb 9 05:11:39 EST 2011
On Wed, Feb 9, 2011 at 11:01 AM, MRAB <python at mrabarnett.plus.com> wrote:
> On 09/02/2011 01:59, Yang Zhang wrote:
>>
>> I reduced a problem I was seeing in my application down into the
>> following test case. In this code, a parent process concurrently
>> spawns 2 (you can spawn more) subprocesses that read a big message
>> from the parent over stdin, sleep for 5 seconds, and write something
>> back. However, there's unexpected waiting happening somewhere, causing
>> the code to complete in 10 seconds instead of the expected 5.
>>
>> If you set `verbose=True`, you can see that the straggling subprocess
>> is receiving most of the messages, then waiting for the last chunk of
>> 3 chars---it's not detecting that the pipe has been closed.
>> Furthermore, if I simply don't do anything with the second process
>> (`doreturn=True`), the first process will *never* see the EOF.
>>
>> Any ideas what's happening? Further down is some example output.
>> Thanks in advance.
>>
>> from subprocess import *
>> from threading import *
>> from time import *
>> from traceback import *
>> import sys
>> verbose = False
>> doreturn = False
>> msg = (20*4096+3)*'a'
>> def elapsed(): return '%7.3f' % (time() - start)
>> if sys.argv[1:]:
>> start = float(sys.argv[2])
>> if verbose:
>> for chunk in iter(lambda: sys.stdin.read(4096), ''):
>> print>> sys.stderr, '..', time(), sys.argv[1], 'read',
>> len(chunk)
>> else:
>> sys.stdin.read()
>> print>> sys.stderr, elapsed(), '..', sys.argv[1], 'done reading'
>> sleep(5)
>> print msg
>> else:
>> start = time()
>> def go(i):
>> print elapsed(), i, 'starting'
>> p = Popen(['python','stuckproc.py',str(i), str(start)],
>> stdin=PIPE, stdout=PIPE)
>> if doreturn and i == 1: return
>> print elapsed(), i, 'writing'
>> p.stdin.write(msg)
>> print elapsed(), i, 'closing'
>> p.stdin.close()
>> print elapsed(), i, 'reading'
>> p.stdout.read()
>> print elapsed(), i, 'done'
>> ts = [Thread(target=go, args=(i,)) for i in xrange(2)]
>> for t in ts: t.start()
>> for t in ts: t.join()
>>
>> Example output:
>>
>> 0.001 0 starting
>> 0.003 1 starting
>> 0.005 0 writing
>> 0.016 1 writing
>> 0.093 0 closing
>> 0.093 0 reading
>> 0.094 1 closing
>> 0.094 1 reading
>> 0.098 .. 1 done reading
>> 5.103 1 done
>> 5.108 .. 0 done reading
>> 10.113 0 done
>>
> I changed 'python' to the path of python.exe and 'stuckproc.py' to its
> full path and tried it with Python 2.7 on Windows XP Pro. It worked as
> expected.
Good point - I didn't specify that I'm seeing this on Linux (Ubuntu
10.04's Python 2.6).
--
Yang Zhang
http://yz.mit.edu/
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