Unpacking multiple dictionaries in a function?

[Peter Otten]

Martin De Kauwe wrote:


> Is there a better way to unpack more than one dictionary in a function
> than...
> 
> def unpack_dicts(f):
>     def wrapper(*old_dicts):
>         dict={}
>         for d in old_dicts:
>             dict.update(d)
>         return f(**dict)
>     return wrapper
> 
> @unpack_dicts
> def some_func(a=None, b=None, c=None):
>     print a, b, c
> 
> d1 = {'a': 20.0, 'b': '-1'}
> d2 = {'c': 33.0}
> 
> some_func(d1, d2)
> 
> thanks

If you had shown a solution involving

>>> dicts = [dict(a=1, b=2, c=3), dict(a=10, b=20, z=40), dict(a=100, 
t=500)]
>>> reduce(lambda a, d: a.update(d) or a, dicts, {})
{'a': 100, 'c': 3, 'b': 20, 't': 500, 'z': 40}

I would have pointed out your approach. So yes, I think you have already 
found the best solution.