list 2 dict?

[Octavian Rasnita]

From: "Ian Kelly" <ian.g.kelly at gmail.com>


> On 1/2/2011 6:18 AM, Octavian Rasnita wrote:
>> Hi,
>>
>> If I want to create a dictionary from a list, is there a better way than the long line below?
>>
>> l = [1, 2, 3, 4, 5, 6, 7, 'a', 8, 'b']
>>
>> d = dict(zip([l[x] for x in range(len(l)) if x %2 == 0], [l[x] for x in range(len(l)) if x %2 == 1]))
> 
> d = dict(zip(l[0::2], l[1::2]))
> 
> Or, using the "grouper" function recipe from the itertools documentation:
> 
> d = dict(grouper(2, l))
> 
> Cheers,
> Ian


The grouper-way looks nice, but I tried it and it didn't work:

from itertools import *
...
d = dict(grouper(2, l))

NameError: name 'grouper' is not defined

I use Python 2.7. Should it work with this version?
Octavian