list 2 dict?

[Stefan Sonnenberg-Carstens]

Am 02.01.2011 16:36, schrieb Octavian Rasnita:
> From: "Ian Kelly"<ian.g.kelly at gmail.com>
>
>
>> On 1/2/2011 6:18 AM, Octavian Rasnita wrote:
>>> Hi,
>>>
>>> If I want to create a dictionary from a list, is there a better way than the long line below?
>>>
>>> l = [1, 2, 3, 4, 5, 6, 7, 'a', 8, 'b']
>>>
>>> d = dict(zip([l[x] for x in range(len(l)) if x %2 == 0], [l[x] for x in range(len(l)) if x %2 == 1]))
>> d = dict(zip(l[0::2], l[1::2]))
>>
>> Or, using the "grouper" function recipe from the itertools documentation:
>>
>> d = dict(grouper(2, l))
>>
>> Cheers,
>> Ian
>
> The grouper-way looks nice, but I tried it and it didn't work:
>
> from itertools import *
> ...
> d = dict(grouper(2, l))
>
> NameError: name 'grouper' is not defined
>
> I use Python 2.7. Should it work with this version?
> Octavian
>
A last one:

l = [1, 2, 3, 4, 5, 6, 7, 'a', 8, 'b']
dict((x[1],x[0]) for x in ((l.pop(),l.pop()) for x in xrange(len(l)/2)))