Am 02.01.2011 14:18, schrieb Octavian Rasnita: > l = [1, 2, 3, 4, 5, 6, 7, 'a', 8, 'b'] l = [1, 2, 3, 4, 5, 6, 7, 'a', 8, 'b'] dict(zip(l[0::2],l[1::2])) {8: 'b', 1: 2, 3: 4, 5: 6, 7: 'a'}