The end to all language wars and the great unity API to come!
kb1pkl at aim.com
Tue Jul 5 12:04:32 EDT 2011
Excerpts from rantingrick's message of Tue Jul 05 07:42:39 -0400 2011:
> I was thinking more about this comment and it occurred to me that
> Python does have user controlled data structures. Just because there
> is no "top level syntax" like ruby does not mean these do not exists.
> You only have to look below the surface. Take the sort methods of
> lists for example...
> >>> lst = [
> (100, 0),
> (25, 2),
> >>> lst
> [(100, 0), (25, 2), (10, 1)]
> >>> lst.sort()
> >>> lst
> [(10, 1), (25, 2), (100, 0)]
> >>> lst.sort(lambda x,y: cmp(x, y))
> >>> lst
> [(100, 0), (10, 1), (25, 2)]
> ...that looks like a "user defined control" structure to me. So how
> can an anti-feature become part of the language proper? (devils
> advocate here) :)
How is giving the sort method a function by which to determine the relative
value of objects a control structure? Do you know what a control structure is?
It's something that you use to modify control flow:
if foo <= bar:
foo += 1
bar += 1
That's a control structurem the "if-else". I don't know what Ruby calls a
control structure, but that's what it is. for and while are in there too.
When you run lst.sort(lambda x, y: cmp(x, y)), what happens?
We'll call that argument srt, here's a sample (naive) implementation:
lst = self.internal_list
for n in range(len(self.internal_list) - 1):
for i in range(len(self.internal_list) - 1):
if srt(lst[i], lst[i+1]) < 0:
lst[i], lst[i+1] = lst[i+1], lst[i]
Untested, probably doesn't work either. See what's in there? An if. Nothing
"user-defined" at all. Sure, WHAT the if does is user-controlled with the
key, but that doesn't make that particular if a new control structure, and
it certainly doesn't make the key a control structure. You can pass a key
to a sort even in C and that certainly doesn't have user defined control
"Those who deny freedom to others, deserve it not for themselves"
-- Abraham Lincoln
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