list comprehension to do os.path.split_all ?

Neil Cerutti neilc at norwich.edu
Thu Jul 28 22:36:41 CEST 2011


On 2011-07-28, gry <georgeryoung at gmail.com> wrote:
> [python 2.7] I have a (linux) pathname that I'd like to split
> completely into a list of components, e.g.:
>    '/home/gyoung/hacks/pathhack/foo.py'  -->  ['home', 'gyoung',
> 'hacks', 'pathhack', 'foo.py']
>
> os.path.split gives me a tuple of dirname,basename, but there's
> no os.path.split_all function.
>
> I expect I can do this with some simple loop, but I have such
> faith in the wonderfulness of list comprehensions, that it
> seems like there should be a way to use them for an elegant
> solution of my problem. I can't quite work it out.  Any
> brilliant ideas?   (or other elegant solutions to the problem?)

If an elegant solution doesn't occur to me right away, then I
first compose the most obvious solution I can think of. Finally,
I refactor it until elegance is either achieved or imagined.

-- 
Neil Cerutti



More information about the Python-list mailing list