list comprehension to do os.path.split_all ?
neilc at norwich.edu
Thu Jul 28 22:36:41 CEST 2011
On 2011-07-28, gry <georgeryoung at gmail.com> wrote:
> [python 2.7] I have a (linux) pathname that I'd like to split
> completely into a list of components, e.g.:
> '/home/gyoung/hacks/pathhack/foo.py' --> ['home', 'gyoung',
> 'hacks', 'pathhack', 'foo.py']
> os.path.split gives me a tuple of dirname,basename, but there's
> no os.path.split_all function.
> I expect I can do this with some simple loop, but I have such
> faith in the wonderfulness of list comprehensions, that it
> seems like there should be a way to use them for an elegant
> solution of my problem. I can't quite work it out. Any
> brilliant ideas? (or other elegant solutions to the problem?)
If an elegant solution doesn't occur to me right away, then I
first compose the most obvious solution I can think of. Finally,
I refactor it until elegance is either achieved or imagined.
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