removing nested iffs

Peter Otten __peter__ at web.de
Sat Jul 30 09:15:51 CEST 2011


Chris Angelico wrote:

> On Sat, Jul 30, 2011 at 6:42 AM, Peter Otten <__peter__ at web.de> wrote:
>> def format_pairs(pairs):
>> for template, value in pairs:
>> if value is None:
>> break
>> yield template.format(value)
>>
> 
> Cool! May I suggest a trifling change:
> 
> def format_pairs(*pairs):
> for template, value in pairs:
> if value is None: break
> yield template.format(value)
> 
> That way, the call can dispense with the [] in the argument list. This
> is a pretty clean solution though, I like it.

Alternatively you can move the list literal into an extra line:

    pairs = [
        ...
    ]
    return "".join(format_pairs(pairs))





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