Of Functions, Objects, and Methods-I NEED HELP PLEASE
Ethan Furman
ethan at stoneleaf.us
Wed Jun 8 16:43:48 EDT 2011
Cathy James wrote:
> I am almost there, but I need a little help:
>
> I would like to
>
> a) print my dogs in the format index. name: breed as follows:
>
> 0. Mimi:Poodle
> 1.Sunny: Beagle
> 2. Bunny: German Shepard
> I am getting
>
> (0, ('Mimi', 'Poodle')) . Mimi : Poodle instead-what have I done wrong?
>
> b) I would like to append to my list, but my line dogs.dogAppend() is
> giving a TypeError:
>
> for i in enumerate (self.dogAppend()):
> TypeError: 'list' object is not callable
>
> Any help?
>
> #MY CODE BELOW:
>
> import sys
> class Dog():
> def __init__(self, name, breed):
> self.name = name
> self.breed = breed
>
> def dogAppend(self):
> self.dogAppend = []
> self.dogAppend.append((self.name,self.breed))
> return self.dogAppend
>
>
> def display (self):
> for i in enumerate (self.dogAppend()):
> print (i,".", self.name, ": " + self.breed)
>
> if __name__ == "__main__":
> dogs = Dog(name=input (" Enter Dog Name: "), breed=input ("Enter
> Dog Breed: "))
> while not dogs:
> print("Goodbye!!")
> sys.exit()
> else:
> #dogs.dogAppend()
> dogs.display()
From the looks of Dog it should only hold one animal, so I would drop
dogAppend and use a normal list; I would also change display to __str__
and remove the enumerate portion (since it's only one animal):
8<----------------------------------------------------------------------
#python 3
class Dog():
def __init__(self, name, breed):
self.name = name
self.breed = breed
def __str__(self):
return self.name + ": " + self.breed
if __name__ == "__main__":
dogs = []
while True:
name=input ("Enter Dog Name: ").rstrip() # stupid newlines
breed=input ("Enter Dog Breed: ").rstrip()
if name and breed:
dogs.append(Dog(name, breed))
for i, dog in enumerate(dogs):
print("%2i. %s" % (i, dog))
else:
print("good-bye")
break
8<----------------------------------------------------------------------
~Ethan~
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