bug in str.startswith() and str.endswith()

Carl Banks pavlovevidence at gmail.com
Thu May 26 20:59:07 EDT 2011


On Thursday, May 26, 2011 4:27:22 PM UTC-7, MRAB wrote:
> On 27/05/2011 00:27, Ethan Furman wrote:
> > I've tried this in 2.5 - 3.2:
> >
> > --> 'this is a test'.startswith('this')
> > True
> > --> 'this is a test'.startswith('this', None, None)
> > Traceback (most recent call last):
> > File "<stdin>", line 1, in <module>
> > TypeError: slice indices must be integers or None or have an __index__
> > method
> >
> > The 3.2 docs say this:
> >
> > str.startswith(prefix[, start[, end]])
> > Return True if string starts with the prefix, otherwise return False.
> > prefix can also be a tuple of prefixes to look for. With optional start,
> > test string beginning at that position. With optional end, stop
> > comparing string at that position
> >
> > str.endswith(suffix[, start[, end]])
> > Return True if the string ends with the specified suffix, otherwise
> > return False. suffix can also be a tuple of suffixes to look for. With
> > optional start, test beginning at that position. With optional end, stop
> > comparing at that position.
> >
> > Any reason this is not a bug?
> >
> Let's see: 'start' and 'end' are optional, but aren't keyword
> arguments, and can't be None...
> 
> I'd say bug.

I also say bug.  The end parameter looks pretty useless for .startswith() and is probably only present for consistency with other string search methods like .index().  Yet on .index() using None as an argument works as intended:

>>> "cbcd".index("c",None,None)
0

So it's there for consistency, yet is not consistent.


Carl Banks



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