scope of function parameters

[Chris Angelico]

On Sun, May 29, 2011 at 10:47 PM, Steven D'Aprano
<steve+comp.lang.python at pearwood.info> wrote:
> If a name is assigned to anywhere in the function, treat it as a local,
> and look it up in the local namespace. If not found, raise
> UnboundLocalError.
>

Wait wha? I've never seen this... wouldn't it just create it in the
local namespace?

Can you give example code that will trigger this error? I'm curious, now...

Chris Angelico