connect SIGINT to custom interrupt handler
Thomas 'PointedEars' Lahn
PointedEars at web.de
Sun May 15 11:43:40 EDT 2011
Christoph Scheingraber wrote:
> I now have signal.siginterrupt(signal.SIGINT, False) in the line
> below signal.signal(signal.SIGINT, interrupt_handler)
>
> Unfortunately, pressing ^c still results in the same interrupt error. I
> also tried putting signal.siginterrupt into the interrupt_handler
> function, which gave an interesting result:
> File "/usr/local/bin/obspysod", line 586, in interrupt_handler
> signal.siginterrupt(signal.SIGINT, False)
> AttributeError: 'int' object has no attribute 'siginterrupt'
>
> Could there be a namespace problem?
Obviously. `signal' refers to an `int' object, probably by something like
signal = 42
before. E.g. `print' or a debugger will tell you, as you have not showed
the relevant parts of the code.
Please trim your quotes to the relevant minimum; DO NOT top-post.
Also, it is not acceptable behavior to use domain namespaces without
authorization (chris at spam.org is not a mailbox, yet spam.org is
registered to someone else).
--
PointedEars
Bitte keine Kopien per E-Mail. / Please do not Cc: me.
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