Help catching error message

[Jean-Michel Pichavant]

Jean-Michel Pichavant wrote:
> Gnarlodious wrote:
>> What I say is this:
>>
>> def SaveEvents(self,events):
>>    try:
>>       plistlib.writePlist(events, self.path+'/Data/Events.plist') #
>> None if OK
>>    except IOError:
>>       return "IOError: [Errno 13] Apache can't write Events.plist
>> file"
>>
>> Note that success returns"None" while failure returns a string.
>>
>> I catch the error like this:
>>
>> errorStatus=Data.Dict.SaveEvents(Data.Plist.Events)
>> if errorStatus: content=errorStatus
>>
>> It works, but isn there a more elegant way to do it? As in, one line?
>> I can imagine if success returned nothing then content would remain
>> unchanged. Isn't there a built-in way to send an error string back and
>> then catch it as a variable name?
>>
>> This is Py3 inside WSGI.
>>
>> -- Gnarlie
>>   
> Hi,
>
> There's no need to rephrase an exception unless you want to *add* 
> information.
>
> def saveEvents(self,events):
>    plistlib.writePlist(events, self.path+'/Data/Events.plist')
> try:      Data.Dict.SaveEvents(Data.Plist.Events)
> except IOError, exc: # i'm using python 2.5, this except clause may 
> have changed in py3
>    content = str(exc)
>
> JM
>
looks like for whatever reason the formating has gone crazy.
http://www.copypastecode.com/100088/

jm