Problem using execvp

[faucheuse]

Hi,

I'm trying to launch my python program with another process name than
"python.exe".
In order to do that I'm trying to use the os.execvp function :

os.execvp("./Launch.py", ["ProcessName"])

Launch.py is the file that Launch the program and ProcessName is
the ... Process Name ^^

I get this error : OSError : [Errno 8] Exec format error.

I searched and found many solutions like : os.execvp("./Launch.py",
["./Launch.py","ProcessName"]), but nothing worked so far.

Can you help me plz ?