socket.getsockname is returning junk!!
Gabriel Genellina
gagsl-py2 at yahoo.com.ar
Fri Oct 7 05:37:12 EDT 2011
En Wed, 05 Oct 2011 08:56:08 -0300, Wong Wah Meng-R32813
<r32813 at freescale.com> escribió:
> I am migrating my application from python 1.5.2 to 2.7.1. One of the
> existing code breaks. The getsockname method from socket object somehow
> returns me with some number which I deem as junk, rather than the
> listening port as I would have expected in the older python. Has anyone
> seen the same thing or is it due to my python is built with some
> corrupted library or something?
>
>
> $ python
> Python 2.7.1 (r271:86832, Oct 5 2011, 18:34:15) [C] on hp-ux11
> Type "help", "copyright", "credits" or "license" for more information.
>>>> import socket
>>>> sock = socket.socket( socket.AF_INET, socket.SOCK_STREAM )
>>>> sock.setsockopt( socket.SOL_SOCKET, socket.SO_REUSEADDR, 1 )
>>>> sock.setsockopt( socket.SOL_SOCKET, socket.SO_KEEPALIVE, 1 )
>>>> sock.setsockopt( socket.IPPROTO_TCP, 1, 1 )
>>>> server_address=('zmy02hp3', 11111)
>>>> sock.bind(server_address)
>>>> sock.getsockname()
> (0, '\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00')
>
> In python 1.5.2
>>>> server_address=('zmy02aix04', 11111)
>>>> sock.bind(server_address)
>>>> sock.getsockname()
> ('10.228.51.41', 11111)
I'd say it's a problem with the _socket module; did the unit tests flag
anything when you built Python?
On Windows, Python 2.7.1:
>>> server_address=('lepton', 11111)
>>> sock.bind(server_address)
>>> sock.getsockname()
('127.0.0.1', 11111)
--
Gabriel Genellina
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