replace random matches of regexp
python at mrabarnett.plus.com
Thu Sep 8 22:12:34 CEST 2011
On 08/09/2011 20:51, gry wrote:
> [Python 2.7]
> I have a body of text (~1MB) that I need to modify. I need to look
> for matches of a regular expression and replace a random selection of
> those matches with a new string. There may be several matches on any
> line, and a random selection of them should be replaced. The
> probability of replacement should be adjustable. Performance is not
> an issue. E.g: if I have:
> SELECT max(PUBLIC.TT.I) AS SEL_0 FROM (SCHM.T RIGHT OUTER JOIN
> PUBLIC.TT ON (SCHM.T.I IS NULL)) WHERE (NOT(NOT((power(PUBLIC.TT.F,
> PUBLIC.TT.F) = cast(ceil(( SELECT 22 AS SEL_0 FROM
> (PUBLIC.TT AS PUBLIC_TT_0 JOIN PUBLIC.TT AS PUBLIC_TT_1 ON (ceil(0.46)
> =sin(PUBLIC_TT_1.F))) WHERE ((zeroifnull(PUBLIC_TT_0.I) =
> sqrt((0.02 + PUBLIC_TT_1.F))) OR
> I might want to replace '(max|min|cos|sqrt|ceil' with "public.\1", but
> only with probability 0.7. I looked and looked for some computed
> thing in re's that I could stick and expression, but could not find
> such(for good reasons, I know).
> Any ideas how to do this? I would go for simple, even if it's wildly
> inefficient, though elegance is always admired...
re.sub can accept a function as the replacement. It'll call the
function when it finds a match, and the string returned by that
function will be the replacement.
You could write a function which returns either the original substring
which was found or a different substring.
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