what's the command for (cd ..) in python

Littlefield, Tyler tyler at tysdomain.com
Fri Sep 9 17:00:32 EDT 2011


On 9/9/2011 6:07 AM, kaustubh joshi wrote:
> Hello friends,
>                          How do we carry out the command "*cd ..*" in 
> python?
>
os.chdir, like so:
 >>> os.getcwd()
'/home/tyler'
 >>> os.chdir("../")
 >>> os.getcwd()
'/home'
So you could do something like: os.chdir("../foo")

> My problem is :
> I have a set of folders say m=1,2,3,4. In each of these folders, I 
> have subfolders with common name say m_5,m_6,m_7,m_8. In each of these 
> subfolder, there is a file which I have edit.
>                                           1                            
>                2                                    3                  
>                    4
>                                          |                            
>                 |                                      |              
>                         |
>                                      
> ------------------------------------------------------------------------------------------------------------------------------------------
>                                   1_5, 1_6, 1_7, 1_8               2_5 
> ,2_6, 2_7, 2_8           3_5, 3_6, 3_7, 3_8          4_5, 4_6, 4_7, 4_8
>
> That is how I designed it
>
> When I run my script, it follows the route 1 ---> 1_5-----> do the 
> edit job in the file. Now it need to change the  subfolder from 1_5 to 
> 1_6, which is not happening.
>
> I created the folders using variable like m for folder taking values 
> 1,2,3,4 and m_n for subfolders with n=5,6,7,8.
>
> I am trying with os.chdir(path), but stuck with how to use m_n in it.
>
> What I am missing at the moment is something that do the job "cd .." does.
>
> Any help
>
>
> Karan
>
>
>


-- 

Take care,
Ty
Web: http://tds-solutions.net

Sent from my toaster.

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