convert time

nn pruebauno at latinmail.com
Mon Sep 12 19:42:35 CEST 2011


On Sep 11, 1:00 am, Steven D'Aprano <steve
+comp.lang.pyt... at pearwood.info> wrote:
> 守株待兔 wrote:
> > how can i convert "Dec 11" into  2011-12?
>
> if my_str == "Dec 11":
>     return 1999  # 2011 - 12
>
> Does that help?
>
> But seriously... 2011-12 is not a proper date, so the simplest way is
> probably something like this:
>
> def convert(date_str):
>     month, short_year = date_str.split()
>     if len(short_year) == 4:
>         year = short_year
>     else:
>         year = '20' + short_year
>     months = 'Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec'.split()
>     month = months.index(month) + 1
>     return year + '-' + str(month)
>
> Otherwise see the time and datetime modules:
>
> http://docs.python.org/library/time.htmlhttp://docs.python.org/library/datetime.html
>
> --
> Steven

Just a small comment that you can get "months" by doing:

from calendar import month_abbr
months = list(month_abbr)



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