回复: strang thing:

守株待兔 1248283536 at qq.com
Tue Sep 13 05:12:03 CEST 2011


i change  open into open1,it's ok now
import os
import  csv

for  name  in   os.listdir('/tmp/quote/'):
    filename='/tmp/quote/'+name
    file = open(filename,'r')
    file.readline()     
    for row in csv.reader(file):
            (date,open1,high,low,close,vol,adjclose) = (row[0], row[1], row[2], row[3],row[4], row[5], row[6])
            print   row[0], row[1], row[2], row[3],row[4], row[5], row[6]


but i want "open"  to be my data field,not  open1  to be my field ,
how can i do?
 
 
------------------ 原始邮件 ------------------
发件人: "Chris Angelico"<rosuav at gmail.com>;
发送时间: 2011年9月6日(星期二) 下午4:22
收件人: "python-list"<python-list at python.org>; 

主题: Re: strang thing:

 
2011/9/6 守株待兔 <1248283536 at qq.com>:
>     file = open(filename,'r')

> when i  add    (date,open,high,low,close,vol,adjclose) = (row[0], row[1],

You're assigning to the name "open", which is shadowing the built-in
of the same name. The second time through the loop, you're not calling
the usual open() function, you're trying to call your string. That's
what your error is telling you.

Hope that helps!

ChrisA
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