Zipping a dictionary whose values are lists
tkpmep at gmail.com
tkpmep at gmail.com
Thu Apr 12 12:28:03 EDT 2012
I using Python 3.2 and have a dictionary
>>> d = {0:[1,2], 1:[1,2,3], 2:[1,2,3,4]}
whose values are lists I would like to zip into a list of tuples. If I explicitly write:
>>> list(zip([1,2], [1,2,3], [1,2,3,4])
[(1, 1, 1), (2, 2, 2)]
I get exactly what I want. On the other hand, I have tried
>>>list(zip(d))
[(0,), (1,), (2,)]
>>> list(zip(d.values()))
[([1, 2],), ([1, 2, 3],), ([1, 2, 3, 4],)]
>>> list(zip(d[i] for i in d))
[([1, 2],), ([1, 2, 3],), ([1, 2, 3, 4],)]
>>> list(zip(*d))
Traceback (most recent call last):
File "<pyshell#48>", line 1, in <module>
list(zip(*d))
TypeError: zip argument #1 must support iteration
and nothing quite works. What am I doing wrong?
Sincerely
Thomas Philips
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