Arithmetic with Boolean values

[Alister]

On Sun, 12 Aug 2012 19:20:26 +0100, Mark Lawrence wrote:

> On 12/08/2012 17:59, Paul Rubin wrote:
>>> which can be simplified to:
>>> for x in range(len(L)//2 + len(L)%2):
>>
>> for x in range(sum(divmod(len(L), 2))): ...
>>
>>
> So who's going to be first in with "and thou shalt not count to 4..."?

Five is right out



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