How do I display unicode value stored in a string variable using ord()

[wxjmfauth at gmail.com]

Le dimanche 19 août 2012 19:03:34 UTC+2, Blind Anagram a écrit :
> "Steven D'Aprano"  wrote in message 
> 
> news:502f8a2a$0$29978$c3e8da3$5496439d at news.astraweb.com...
> 
> 
> 
> On Sat, 18 Aug 2012 01:09:26 -0700, wxjmfauth wrote:
> 
> 
> 
> [...]
> 
> If you can consistently replicate a 100% to 1000% slowdown in string
> 
> handling, please report it as a performance bug:
> 
> 
> 
> http://bugs.python.org/
> 
> 
> 
> Don't forget to report your operating system.
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> 
> 
> ====================================================
> 
> For interest, I ran your code snippets on my laptop (Intel core-i7 1.8GHz) 
> 
> running Windows 7 x64.
> 
> 
> 
> Running Python from a Windows command prompt,  I got the following on Python 
> 
> 3.2.3 and 3.3 beta 2:
> 
> 
> 
> python33\python" -m timeit "('abc' * 1000).replace('c', 'de')"
> 
> 10000 loops, best of 3: 39.3 usec per loop
> 
> python33\python" -m timeit "('ab…' * 1000).replace('…', '……')"
> 
> 10000 loops, best of 3: 51.8 usec per loop
> 
> python33\python" -m timeit "('ab…' * 1000).replace('…', 'x…')"
> 
> 10000 loops, best of 3: 52 usec per loop
> 
> python33\python" -m timeit "('ab…' * 1000).replace('…', 'œ…')"
> 
> 10000 loops, best of 3: 50.3 usec per loop
> 
> python33\python" -m timeit "('ab…' * 1000).replace('…', '€…')"
> 
> 10000 loops, best of 3: 51.6 usec per loop
> 
> python33\python" -m timeit "('XYZ' * 1000).replace('X', 'éç')"
> 
> 10000 loops, best of 3: 38.3 usec per loop
> 
> python33\python" -m timeit "('XYZ' * 1000).replace('Y', 'p?')"
> 
> 10000 loops, best of 3: 50.3 usec per loop
> 
> 
> 
> python32\python" -m timeit "('abc' * 1000).replace('c', 'de')"
> 
> 10000 loops, best of 3: 24.5 usec per loop
> 
> python32\python" -m timeit "('ab…' * 1000).replace('…', '……')"
> 
> 10000 loops, best of 3: 24.7 usec per loop
> 
> python32\python" -m timeit "('ab…' * 1000).replace('…', 'x…')"
> 
> 10000 loops, best of 3: 24.8 usec per loop
> 
> python32\python" -m timeit "('ab…' * 1000).replace('…', 'œ…')"
> 
> 10000 loops, best of 3: 24 usec per loop
> 
> python32\python" -m timeit "('ab…' * 1000).replace('…', '€…')"
> 
> 10000 loops, best of 3: 24.1 usec per loop
> 
> python32\python" -m timeit "('XYZ' * 1000).replace('X', 'éç')"
> 
> 10000 loops, best of 3: 24.4 usec per loop
> 
> python32\python" -m timeit "('XYZ' * 1000).replace('Y', 'p?')"
> 
> 10000 loops, best of 3: 24.3 usec per loop
> 
> 
> 
> This is an average slowdown by a factor of close to 2.3 on 3.3 when compared 
> 
> with 3.2.
> 
> 
> 
> I am not posting this to perpetuate this thread but simply to ask whether, 
> 
> as you suggest, I should report this as a possible problem with the beta?

I use win7 pro 32bits in intel?

Thanks for reporting these numbers.
To be clear: I'm not complaining, but the fact that
there is a slow down is a clear indication (in my mind),
there is a point somewhere.

jmf