issue with struct.unpack
9bizy
a.m.akingbulu-11 at student.lboro.ac.uk
Tue Aug 28 19:01:40 EDT 2012
On Tuesday, 28 August 2012 23:49:54 UTC+1, MRAB wrote:
> On 28/08/2012 23:34, 9bizy wrote:
>
> > This is what I have to reproduce the challenge I am having below:
>
> >
>
> >
>
> > import csv
>
> > import struct
>
> >
>
> >
>
> > data = []
>
> >
>
> > for Node in csv.reader(file('s_data.xls')):
>
>
>
> That tries to read the file as CSV, but, judging from the extension,
>
> it's in Excel's format. You don't even use what is read, i.e. Node.
>
>
>
> > data.append(list((file('s_data.xls'))))
>
> >
>
> That opens the file again and 'list' causes it to read the file as
>
> though it were a series of lines in a text file, which, as I've said,
>
> it looks like it isn't. The list of 'lines' is appended to the list
>
> 'data', so that's a list of lists.
>
> >
>
> > data = struct.unpack('!B4HH', data)
>
> > print "s_data.csv: ", data
>
> >
>
> > I tries so many format for the struct.unpack but I got this errors:
>
> >
>
> > Traceback (most recent call last):
>
> >
>
> > data = struct.unpack('!B4HH', data)
>
> > struct.error: unpack requires a string argument of length 11
>
> >
>
> [snip]
>
> It's complaining because it's expecting a string argument but you're
>
> giving it a list instead.
How do I then convert data to a string argument in this case?
More information about the Python-list
mailing list