counting how often the same word appears in a txt file...But my code only prints the last line entry in the txt file

dgcosgrave at gmail.com dgcosgrave at gmail.com
Wed Dec 19 12:28:40 CET 2012


On Wednesday, December 19, 2012 11:55:28 PM UTC+13, Jussi Piitulainen wrote:
> 
> 
> 
> 
> > Hi Iam just starting out with python...My code below changes the txt
> 
> > file into a list and add them to an empty dictionary and print how
> 
> > often the word occurs, but it only seems to recognise and print the
> 
> > last entry of the txt file. Any help would be great.
> 
> > 
> 
> > tm =open('ask.txt', 'r')
> 
> > dict = {}
> 
> > for line in tm:
> 
> > 	line = line.strip()
> 
> > 	line = line.translate(None, '!"#$%&\'()*+,-./:;<=>?@[\\]^_`{|}~')
> 
> > 	line = line.lower()
> 
> > 	list = line.split(' ')
> 
> > for word in list:	
> 
> > 		if word in dict:
> 
> > 			count = dict[word]
> 
> > 			count += 1
> 
> > 			dict[word] = count
> 
> > else:
> 
> > 	dict[word] = 1
> 
> > for word, count in dict.iteritems():
> 
> > 	print word + ":" + str(count)
> 
> 
> 
> The "else" clause is mis-indented (rather, mis-unindented).
> 
> 
> 
> Python's "for" statement does have an optional "else" clause. That's
> 
> why you don't get a syntax error. The "else" clause is used after the
> 
> loop finishes normally. That's why it catches the last word.

Thanks for quick reply Jussi...indentation fixed the problem :-)



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