Integer as raw hex string?
python.list at tim.thechases.com
Mon Dec 24 16:58:01 CET 2012
On 12/24/12 09:36, Roy Smith wrote:
> I have an integer that I want to encode as a hex string, but I don't
> want "0x" at the beginning, nor do I want "L" at the end if it happened
> to be a long. The result needs to be something I can pass to int(h, 16)
> to get back my original integer.
> The brute force way works:
> h = hex(i)
> assert h.startswith('0x')
> h = h[2:]
> if h.endswith('L'):
> h = h[:-1]
> but I'm wondering if there's some built-in call which gives me what I
> want directly. Python 2.7.
Would something like
h = "%08x" % i
h = "%x" % i
work for you?
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