Integer as raw hex string?

Roy Smith roy at panix.com
Mon Dec 24 17:21:15 CET 2012


In article <mailman.1256.1356364625.29569.python-list at python.org>,
 Tim Chase <python.list at tim.thechases.com> wrote:

> On 12/24/12 09:36, Roy Smith wrote:
> > I have an integer that I want to encode as a hex string, but I don't 
> > want "0x" at the beginning, nor do I want "L" at the end if it happened 
> > to be a long.  The result needs to be something I can pass to int(h, 16) 
> > to get back my original integer.
> > 
> > The brute force way works:
> > 
> >    h = hex(i)
> >    assert h.startswith('0x')
> >    h = h[2:]
> >    if h.endswith('L'):
> >        h = h[:-1]
> > 
> > but I'm wondering if there's some built-in call which gives me what I 
> > want directly.  Python 2.7.
> 
> Would something like
> 
>   h = "%08x" % i
> 
> or
> 
>   h = "%x" % i
> 
> work for you?

Duh.  Of course.  Thanks.



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