Integer as raw hex string?
roy at panix.com
Mon Dec 24 17:21:15 CET 2012
In article <mailman.1256.1356364625.29569.python-list at python.org>,
Tim Chase <python.list at tim.thechases.com> wrote:
> On 12/24/12 09:36, Roy Smith wrote:
> > I have an integer that I want to encode as a hex string, but I don't
> > want "0x" at the beginning, nor do I want "L" at the end if it happened
> > to be a long. The result needs to be something I can pass to int(h, 16)
> > to get back my original integer.
> > The brute force way works:
> > h = hex(i)
> > assert h.startswith('0x')
> > h = h[2:]
> > if h.endswith('L'):
> > h = h[:-1]
> > but I'm wondering if there's some built-in call which gives me what I
> > want directly. Python 2.7.
> Would something like
> h = "%08x" % i
> h = "%x" % i
> work for you?
Duh. Of course. Thanks.
More information about the Python-list