email.message.Message - as_string fails

Helmut Jarausch jarausch at
Fri Dec 28 13:22:51 CET 2012


I'm trying to filter an mbox file by removing some messages.
For that I use 
Parser= FeedParser(policy=policy.SMTP)
and 'feed' any lines to it.
If the mbox file contains a white line followed by '^From ',
I do

Msg= Parser.close()

(lateron I delete the Parser and create a new one by
Parser= FeedParser(policy=policy.SMTP)

I can access parts of the message by  Msg['Message-ID'], e.g.
but even for the very first message, trying to print it or convert it to a string
by  MsgStr=Msg.as_string(unixfrom=True)

lets Python (3.3.1_pre20121209) die with

Traceback (most recent call last):
  File "", line 35, in <module>
  File "/usr/lib64/python3.3/email/", line 151, in as_string
    g.flatten(self, unixfrom=unixfrom)
  File "/usr/lib64/python3.3/email/", line 112, in flatten
  File "/usr/lib64/python3.3/email/", line 171, in _write
  File "/usr/lib64/python3.3/email/", line 198, in _write_headers
    self.write(self.policy.fold(h, v))
  File "/usr/lib64/python3.3/email/", line 153, in fold
    return self._fold(name, value, refold_binary=True)
  File "/usr/lib64/python3.3/email/", line 176, in _fold
    (len(lines[0])+len(name)+2 > maxlen or
IndexError: list index out of range

What am I missing?

Many thanks for a hint,

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