random number
Steven D'Aprano
steve+comp.lang.python at pearwood.info
Mon Mar 26 09:24:38 CEST 2012
On Mon, 26 Mar 2012 08:40:00 +0200, Michael Poeltl wrote:
> * Nikhil Verma <varma.nikhil22 at gmail.com> [2012-03-26 08:09]:
>> Hi All
>>
>> How can we generate a 6 digit random number from a given number ?
> what about this?
>
>>>> given_number=123456
>>>> def rand_given_number(x):
> ... s = list(str(x))
> ... random.shuffle(s)
> ... return int(''.join(s))
> ...
>>>> print (rand_given_number(given_number))
> 653421
That's not very random. In fact, it is *terrible* as a random number
generator.
A truly random six digit number will include any number between 100000
through 999999. There are exactly 900000 (nine hundred thousand) such
numbers.
The way you generate the not-quite-random numbers, you miss out on almost
all of them. E.g. you can generate 123456 but not 123455 or 123457.
In total, you generate only 6! = 6*5*4*3*2*1 = 720 numbers, no matter how
many millions of times you call the function. Here is a demonstration:
>>> given = 123456
>>> def rand_num(x):
... s = list(str(x))
... random.shuffle(s)
... return int(''.join(s))
...
>>> import random
>>> results = set()
>>> for i in range(10**7):
... results.add(rand_num(given))
...
>>> len(results)
720
So slightly more than 99% of all the six digit numbers will never be
generated using your method.
--
Steven
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