Jython callable. How?
Sirotin Roman
web.elektro.net at gmail.com
Sun Mar 4 09:14:46 EST 2012
> Perhaps if you show us what you actually do, and what happens, we might
> be able to tell you what is happening. Please COPY AND PASTE the full
> traceback.
Here is my code:
# Trying to make callable staticmethod
class sm(staticmethod):
def __call__(self, *args, **kwargs):
""" I know here is one more potential problem, because object
passed instead of real class """
return self.__get__(None, object)(*args, **kwargs)
issubclass(sm, Callable)
class Foo(object):
@sm
def bar():
print("ololo")
print("inside", bar, callable(bar), bar())
if __name__=="__main__":
print("class outise", Foo.bar, callable(Foo.bar), Foo.bar())
f = Foo()
print("instance outside", f.bar, callable(f.bar), f.bar())
cpython output:
ololo
('inside', <__main__.sm object at 0xb72b404c>, True, None)
ololo
('class outise', <function bar at 0xb72a680c>, True, None)
ololo
('instance outside', <function bar at 0xb72a680c>, True, None)
jython output:
Traceback (most recent call last):
File "sm.py", line 17, in <module>
class Foo(object):
File "sm.py", line 23, in Foo
print("inside", bar, callable(bar), bar())
TypeError: 'staticmethod' object is not callable
More information about the Python-list
mailing list