local variable 'a' referenced b
contro opinion
contropinion at gmail.com
Tue Oct 2 22:03:20 EDT 2012
code1
>>> def foo():
... a = 1
... def bar():
... b=2
... print a + b
... bar()
...
...
>>> foo()
3
code2
>>> def foo():
... a = 1
... def bar():
... b=2
... a = a + b
... print a
... bar()
...
>>> foo()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 7, in foo
File "<stdin>", line 5, in bar
UnboundLocalError: local variable 'a' referenced b
why code2 can not get output of 3?
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