Function for examine content of directory
Tigerstyle
laddosingh at gmail.com
Fri Sep 7 10:23:15 EDT 2012
kl. 16:56:29 UTC+2 torsdag 6. september 2012 skrev Tigerstyle følgende:
> Hi guys,
>
>
>
> I'm trying to write a module containing a function to examine the contents of the current working directory and print out a count of how many files have each extension (".txt", ".doc", etc.)
>
>
>
> This is the code so far:
>
> --
>
> import os
>
>
>
> path = "v:\\workspace\\Python2_Homework03\\src\\"
>
> dirs = os.listdir( path )
>
> filenames = {"this.txt", "that.txt", "the_other.txt","this.doc","that.doc","this.pdf","first.txt","that.pdf"}
>
> extensions = []
>
> for filename in filenames:
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> f = open(filename, "w")
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> f.write("Some text\n")
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> f.close()
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> name , ext = os.path.splitext(f.name)
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> extensions.append(ext)
>
>
>
> # This would print all the files and directories
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> for file in dirs:
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> print(file)
>
>
>
> for ext in extensions:
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> print("Count for %s: " %ext, extensions.count(ext))
>
>
>
> --
>
>
>
> When I'm trying to get the module to print how many files each extension has, it prints the count of each ext multiple times for each extension type. Like this:
>
>
>
> this.pdf
>
> the_other.txt
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> this.doc
>
> that.txt
>
> this.txt
>
> that.pdf
>
> first.txt
>
> that.doc
>
> Count for .pdf: 2
>
> Count for .txt: 4
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> Count for .doc: 2
>
> Count for .txt: 4
>
> Count for .txt: 4
>
> Count for .pdf: 2
>
> Count for .txt: 4
>
> Count for .doc: 2
>
>
>
> Any help is appreciated.
>
>
>
> T
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