using "*" to make a list of lists with repeated (and independent) elements
Paul Rubin
no.email at nospam.invalid
Wed Sep 26 17:43:58 EDT 2012
TP <TP at frenoespam.fr.invalid> writes:
> copies a list, he copies in fact the *pointer* to the list ....
> Is it the correct explanation?
Yes, that is correct.
> In these conditions, how to make this list [[0,0,0],[0,0,0]] with "*"
> without this behavior?
>>> a = [[0]*3 for i in xrange(2)]
>>> a[0][0]=2
>>> a
[[2, 0, 0], [0, 0, 0]]
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