using "*" to make a list of lists with repeated (and independent) elements
88888 Dihedral
dihedral88888 at googlemail.com
Wed Sep 26 18:07:35 EDT 2012
Paul Rubin於 2012年9月27日星期四UTC+8上午5時43分58秒寫道:
> TP <TP at frenoespam.fr.invalid> writes:
>
> > copies a list, he copies in fact the *pointer* to the list ....
>
> > Is it the correct explanation?
>
>
>
> Yes, that is correct.
>
>
>
> > In these conditions, how to make this list [[0,0,0],[0,0,0]] with "*"
>
> > without this behavior?
>
>
>
> >>> a = [[0]*3 for i in xrange(2)]
>
> >>> a[0][0]=2
>
> >>> a
>
> [[2, 0, 0], [0, 0, 0]]
I used numpy before.
Python is not lisp but python can emulate the lisp behaviors.
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