reduce expression to test sublist
yacinechaouche at yahoo.com
Sat Jan 5 20:59:56 CET 2013
Because reduce doesn't do what you want. You'd want "all".
L1 = [1,2,3]
L2 = ["A1","B2","C3",1,2,3]
print all((x in L2 for x in L1)) # prints True
L3 = ["A1","B2","C3"]
print all((x in L2 for x in L3)) # prints True
----- Original Message -----
From: Asim <asim.r.p at gmail.com>
To: python-list at python.org
Sent: Saturday, January 5, 2013 7:25 PM
Subject: reduce expression to test sublist
The following reduce expression checks if every element of list lst1 is present in list lst2. It works as expected for integer lists but for lists of strings, it always returns False.
reduce( lambda x,y: (x in lst2) and (y in lst2), lst1)
Moreover, for the lists of strings the following for-loop gives correct results when the above reduce expression doesn't.
isSublist = True
for i in lst1:
isSublist = isSublist and (i in lst2)
if not isSublist:
isSublist = False
Can someone help me understand why?
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