[os.path.join(r'E:\Python', name) for name in ] returns 
rosuav at gmail.com
Wed Jan 30 03:17:03 CET 2013
On Wed, Jan 30, 2013 at 12:56 PM, iMath <redstone-cold at 163.com> wrote:
> 在 2013年1月29日星期二UTC+8下午9时33分26秒，Steven D'Aprano写道：
>> iMath wrote: > why [os.path.join(r'E:\Python', name) for name in ] returns  ? Because you are iterating over an empty list, . That list comprehension is the equivalent of: result =  for name in : result.append( os.path.join(r'E:\Python', name) ) Since you iterate over an empty list, the body of the loop never executes, and the result list remains empty. What did you expect it to do? -- Steven
> just in order to get the full path name of each file .
Then it's done exactly what it should. It's given you the full path of
all of your list of zero files.
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