sqlite3 puzzle
Rob Day
robert.day at merton.oxon.org
Tue Jan 15 09:36:51 EST 2013
On 15 January 2013 07:09, llanitedave <llanitedave at veawb.coop> wrote:
> So I put the following test code in my initialization method:
>
> # open database file
> self.geologger_db = sqlite3.connect('geologger.mgc')
> self.db_cursor = self.geologger_db.cursor()
> self.foreign_key_status = self.db_cursor.execute("PRAGMA foreign_keys = ON")
> self.foreign_key_status = self.foreign_key_status.fetchone()
>
> print self.foreign_key_status
>
> I ran this several times while I was arranging the downstream queries, and each time it returned '(1,)', which means foreign keys is enabled.
>
> But I was using a variable named 'cmd1' as a placeholder until I changed the name to
> the more descriptive 'self.foreign_key_status'. Since I made the name change, however,
> the code only returns 'None'. Reverting to the previous variable name has no effect.
Hmm - your code doesn't quite match up with the docs at
http://docs.python.org/2/library/sqlite3.html. That seems to suggest
that you should call fetchone() on the cursor, not on the result of
execute().
Does the following work?
# open database file
self.geologger_db = sqlite3.connect('geologger.mgc')
self.db_cursor = self.geologger_db.cursor()
self.db_cursor.execute("PRAGMA foreign_keys = ON")
print self.db_cursor.fetchone()
--
Robert K. Day
robert.day at merton.oxon.org
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