create object base on text file
cxleung at gmail.com
cxleung at gmail.com
Fri Jan 25 10:28:52 EST 2013
On Friday, January 25, 2013 9:04:31 PM UTC+8, Dave Angel wrote:
> On 01/25/2013 07:06 AM, moonhkt wrote:
>
> > Hi All
>
> >
>
> > Python 2.6.x on AIX
>
> >
>
> > Data file
>
> >
>
> > PrinterA
>
> > print Production batch1
>
> > xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
>
> > print Production batch2
>
> > xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
>
> > print Production batch3
>
> > xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
>
> >
>
> > PrinterB
>
> > print Production batch4
>
> > xxxxxxxxxxxxxxxxxxxxxxxxxxx
>
> > print Production batch5
>
> > xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
>
> >
>
> >
>
> > What to using python create object base on date file ? I know how to
>
> > read text file.
>
> >
>
> > object["PrinterA"] have batch1, batch2, batch3
>
> >
>
> > object["PrinterB"] have batch4, batch5
>
> >
>
> > moonhkt
>
> >
>
>
>
> What Python version are you targeting?
>
>
>
> It would save everyone a lot of time if you quoted the homework
>
> assignment directly. Also, be more careful about typos. Is it a date
>
> file, or a data file?
>
>
>
> You can create an object very easily. a = object(). You can add
>
> attributes to many objects by simply saying
>
> a.attrib = 42
>
>
>
> Unfortunately you can't do that to an "object" class instance. So you
>
> need to clarify.
>
>
>
> Now, you used dictionary syntax, so perhaps you didn't mean create an
>
> object, but create a dict.
>
>
>
> a = dict()
>
> a["PrinterA"] = "batch1", "batch2", "batch3"
>
> print a
>
>
>
> produces
>
> {'PrinterA': ('batch1', 'batch2', 'batch3')}
>
>
>
>
>
> What part of the assignment is giving you trouble? What have you
>
> written so far?
>
>
>
>
>
> --
>
> DaveA
Thank I get the methods.
Python 2.6.2
I just leaning python , before using gawk/ksh.
#!/usr/bin/env python
a= dict()
a["PrintA"]= ["batch1","batch2","batch3"]
a["PrintB"] = ["batch4","batch5"]
a["PrintA"].append("batch6")
print a
for k in sorted(a.keys()):
for j in sorted(a[k]):
print k , j
Output
{'PrintA': ['batch1', 'batch2', 'batch3', 'batch6'], 'PrintB': ['batch4', 'batch5']}
PrintA batch1
PrintA batch2
PrintA batch3
PrintA batch6
PrintB batch4
PrintB batch5
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