how to calculate reputation
Steven D'Aprano
steve+comp.lang.python at pearwood.info
Tue Jul 2 20:18:26 EDT 2013
On Tue, 02 Jul 2013 23:43:51 +0200, Surya Kasturi wrote:
> Hi all, this seems to be quite stupid question but I am "confused".. We
> set the initial value to 0, +1 for up-vote and -1 for down-vote! nice.
>
> I have a list of bool values True, False (True for up vote, False for
> down-vote).. submitted by users.
>
> [True, False, False, True....]
>
> Now to calculate the total reputation
>
> should I take True = +1, False=0 [or] True = +1, False=-1 ?? for adding
> all.
You can work this out for yourself by doing a couple of tests. Suppose
you have somebody who gets one Upvote and five Downvotes:
[True, False, False, False, False, False]
What reputation would you expect them to have? We can't answer that, only
you can answer that.
With True=+1 and False=0, the sum is +1.
With True=+1 and False=-1, the sum is -4.
Upvotes and downvotes don't have to be weighted the same:
With True=+5 and False=-1, the sum is 0.
With True=+1 and False=-5, the sum is -24.
*You* have to decide how you want the reputation system to work, then
program it to work that way.
For a real web app, you almost certainly do not want something this
simple. Perhaps new accounts with low reputation themselves should be
weighted less than old, established accounts with high reputation. There
is no standard for counting reputation, and so every web site that does
something like this does it differently, and most get it wrong, including
some really big, well-known sites like Amazon.
It's very easy to come up with lousy algorithms for calculating
reputation, much harder to come up with good algorithms. I second Joshua
Landau's recommendation that you read:
http://www.evanmiller.org/how-not-to-sort-by-average-rating.html
and I bring to your attention that this doesn't necessarily have anything
to do with *sorting*. The Ruby function given returns a number between 0
and 1. You don't have to sort on that number, you can use that as your
reputation.
--
Steven
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