trigger at TDM/2 only
Dave Angel
davea at davea.name
Thu Jun 6 20:43:11 EDT 2013
On 06/06/2013 08:03 PM, cerr wrote:
> Hi,
>
> I have a process that I can trigger only at a certain time. Assume I have a TDM period of 10min, that means, I can only fire my trigger at the 5th minute of every 10min cycle i.e. at XX:05, XX:15, XX:25... For hat I came up with following algorithm which oly leaves the waiting while loop if minute % TDM/2 is 0 but not if minute % TDM is 0:
> min = datetime.datetime.now().timetuple().tm_hour*60 + datetime.datetime.now().timetuple().tm_min
> while not (min%tdm_timeslot != 0 ^ min%(int(tdm_timeslot/2)) != 0):
You might have spent three minutes and simplified this for us. And in
the process discovered the problem.
(BTW, min() is a builtin function, so it's not really a good idea to be
shadowing it.)
You didn't give python version, so my sample is assuming Python 2.7
For your code it shouldn't matter.
tdm = 10
tdm2 = 5
y = min(3,4)
print y
for now in range(10,32):
print now, now%tdm, now%tdm2,
print not(now % tdm !=0 ^ now%tdm2 !=0) #bad
print not((now % tdm !=0) ^ (now%tdm2 !=0)) #good
Your problem is one of operator precedence. Notice that ^ has a higher
precedence than != operator, so you need the parentheses I added in the
following line.
What I don't understand is why you used this convoluted approach. Why not
print now%tdm != tdm2
For precedence rules, see:
http://docs.python.org/2/reference/expressions.html#operator-precedence
--
DaveA
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