Sorting (deeply) nested lists

mamboknave at mamboknave at
Sat Mar 2 18:49:00 CET 2013

On Saturday, March 2, 2013 9:36:43 AM UTC-8, Peter Otten wrote:
> You can also write this as
> namedTuples.sort(key=lambda item: item[1][1])

That's exactly what I did before and got "IndexError: list index out of range".

So, I thought my lambda was wrong and posted here.

Now, having seen you reply, I dug deeper and... of course I had IndexError: the list was horribly empty!

Thanks so much for replying so quickly, Peter!

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